中三數~快~要式~(根式)~(40分)~!!!－oqg08ig24q的部落格

標題:

中三數~快~要式~(根式)~(40分)~!!!

發問:

1. 4 . ───────── . (√13/4)+(√13/3) . =???(要式) . =16√3/13(這是答案) 更新: 1. 4/(√13/4)+(√13/3)

最佳解答:

(√13/4)+(√13/3) (3√13/12)+(4√13/12) 通分 7√13/12 2012-06-09 16:33:22 補充： 4/(√13/4)+(√13/3) 4×(4/√13)+(√13/3) (16/√13)+(√13/3) (16×√13)/(√13×√13)+(√13/3) (16√13/13)+(√13/3) (3×16√13/13×3)+(13×√13/3×13) 48√13/39+13√13/39 61√13/39 2012-06-09 16:42:39 補充： 4/√(13/4)+√(13/3) =4/〔√(13)/√(4)〕+√(13)/√(3) =4/〔√(13)/2〕+√(13)/√(3) =4×〔2/√(13)〕+√(13)/√(3) =8/√(13)+√(13)/√(3) =8√(13)/13+√(13)√(3)/3 =8√(13)/13+√(39)/3 2012-06-09 16:46:39 補充：我都5明你表達的式. √(2/3)≠(√2/3) √(2/3)=√(2)/√(3) (√2/3)=√(2)/3 2012-06-09 16:50:45 補充： √(13/3)都不可

其他解答:

no way to get a sqrt(3) as ans- -.....|||||Can you type the Q more clearly? 2012-06-09 13:47:40 補充： (4/(√13/4))+(√13/3) or 4/((√13/4)+(√13/3)) ?? 2012-06-09 13:48:19 補充： Neither of these = 16√3/13 ! 2012-06-09 14:51:04 補充： Maybe he mean √(13/3) ?