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標題:
數學問題 20點 【急】
發問:
In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE. http://www.pic-upload.de/18.03.09/yn5ll.jpg or http://www.pic-upload.de/view-1694505/-12.jpg.html
最佳解答:
http://www.pic-upload.de/view-1694962/Solution.jpg.html AD=AF AE=AF+FE AE=AD+FE So, AD
其他解答:
NO thats all of the question|||||In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE. In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE. In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE.|||||Is there any information missing? Such as AB is perpendicular to DF.
數學問題 20點 【急】
發問:
In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE. http://www.pic-upload.de/18.03.09/yn5ll.jpg or http://www.pic-upload.de/view-1694505/-12.jpg.html
最佳解答:
http://www.pic-upload.de/view-1694962/Solution.jpg.html AD=AF AE=AF+FE AE=AD+FE So, AD
其他解答:
NO thats all of the question|||||In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE. In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE. In the figure, AB=AC. A straight line meets AB and AC at D and E respectively. It also meets BC When produced at F. Prove That AD < AE.|||||Is there any information missing? Such as AB is perpendicular to DF.
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