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Pls adv solution & answer of 5 question:Question 1Last year, Mrs Chan's weight was 3 time of her son's weight. This year, her son's weight increaes by 10% while her weight decreases by 10%. Mrs Chan is now 32kg heavier than her son. Find Mrs Chan's weight last... 顯示更多 Pls adv solution & answer of 5 question: Question 1 Last year, Mrs Chan's weight was 3 time of her son's weight. This year, her son's weight increaes by 10% while her weight decreases by 10%. Mrs Chan is now 32kg heavier than her son. Find Mrs Chan's weight last year. Question 2 A furniture manufacturer sold a chair and a table for $X and $2.5X respectively to a merchant. The merchant then sold the chair at a loss of 40% and the table at a profit of 40%. Did the merchant make an overall profit or loss, and by what per cent? Question 3 Dorothy bought a teddy bear and sold it at 20% profit to Kim. Kim bought a suit costing $100 and dressed the teddy bear up in the suit. Kim then sold the teddy bear in the suit to Karen for $442. Kim made a profit of 30%. What was the price that Dorothy paid for the teddy bear? Question 4 In a book shop, the initial profit made by selling a calendar was $18. After 2/5 of calendars had been sold, the bookseller reduced the price of each calendar by $10. It is given that if all the calendars were sold, the bookseller made an overall profit of $3000. a)Find the total number of calendars he had originally. b)If only a further 100 calendars were sold after the price reduction and the rest were discarded, and the bookseller made an overall profit per cent of 20%, find the total cost of the calendars. Question 5 A shop spends $2400 on 1 batch of basketballs and footballs. There are 15 more baskerballs than footballs. The selling price of a basketball is 20% higher than that of a football. The selling price of each footballs is $60. a)If all the basketballs and footballs are sold, and the overall profit is $660, how many basketballs and footballs has the shop sold? Urgently waiting for help.....Thanks
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Question 1 Last year, Mrs Chan's weight was 3 time of her son's weight. This year, her son's weight increaes by 10% while her weight decreases by 10%. Mrs Chan is now 32kg heavier than her son. Find Mrs Chan's weight last year. let Mrs Chan's weight be 3x kg and her son be x kg 3x(1-10%) - x(1+10%) = 32 3x(0.9) - x(1.1) = 32 2.7x - 1.1x = 32 1.6x = 32 x= 20 therefore Mrs Chan's weight is 3 x 20 = 60kg her son is 20kg Question 2 A furniture manufacturer sold a chair and a table for $X and $2.5X respectively to a merchant. The merchant then sold the chair at a loss of 40% and the table at a profit of 40%. Did the merchant make an overall profit or loss, and by what per cent? the cost of chair and table: X + 2.5X = $3.5X profit of selling the chair: X(1-40%) = X(0.6) = $0.6X profit of selling the table: 2.5X(1+40%) = 2.5X(1.4) = $3.5X Total profit of selling both chair and table = 0.6X + 3.5X = $4.1X (4.1X - 3.5X) / 3.5X * 100% = 17.14% (round up to two decimials) therefore, the merchant make a overall profit of 17.14% Question 3 Dorothy bought a teddy bear and sold it at 20% profit to Kim. Kim bought a suit costing $100 and dressed the teddy bear up in the suit. Kim then sold the teddy bear in the suit to Karen for $442. Kim made a profit of 30%. What was the price that Dorothy paid for the teddy bear? Let the price that Dorothy paid for the teddy bear be $x then Dorothy sold to Kim at x(1+20%) = $1.2x to Kim Kim sold to Karen at (1.2x+100) x (1+30%) = 442 (1.2x+100) = 442 / 1.3 1.2x = 340 -100 1.2x = 240 x = 200 therefore the price that Dorothy paid for the teddy bear is $200 2009-11-29 16:41:07 補充： 4a)Find the total number of calendars he had originally. Let the number of calendars he had originally be x 18(2/5x) + (18-10)(1-2/5)x = 3000 36/5x + 24/5x = 3000 60/5x = 3000 12x = 3000 x = 250 therefore the number of calendars he had originally is 250. 2009-11-29 16:42:08 補充： 4(b) The new profit made: 18(2/5 * 250) + (18-10) * 100 = $2600 The the total cost of calendars are: 2600 / 20% = $13000 2009-11-29 16:42:14 補充： 5a) Let the number of footballs be x and the number of basketballs be (x +15) total selling price = [60x + (1+20%)(60)(x+15)] = 60x + 72x + 1080 = 132x +1080 overall profit is (132x + 1080) - 2400 = 660 132x = 1980 x=15 therefore, the shop is selling 15 football and (15+15) = 30 basdketballs no b?
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Pls adv solution & answer of 5 question:Question 1Last year, Mrs Chan's weight was 3 time of her son's weight. This year, her son's weight increaes by 10% while her weight decreases by 10%. Mrs Chan is now 32kg heavier than her son. Find Mrs Chan's weight last... 顯示更多 Pls adv solution & answer of 5 question: Question 1 Last year, Mrs Chan's weight was 3 time of her son's weight. This year, her son's weight increaes by 10% while her weight decreases by 10%. Mrs Chan is now 32kg heavier than her son. Find Mrs Chan's weight last year. Question 2 A furniture manufacturer sold a chair and a table for $X and $2.5X respectively to a merchant. The merchant then sold the chair at a loss of 40% and the table at a profit of 40%. Did the merchant make an overall profit or loss, and by what per cent? Question 3 Dorothy bought a teddy bear and sold it at 20% profit to Kim. Kim bought a suit costing $100 and dressed the teddy bear up in the suit. Kim then sold the teddy bear in the suit to Karen for $442. Kim made a profit of 30%. What was the price that Dorothy paid for the teddy bear? Question 4 In a book shop, the initial profit made by selling a calendar was $18. After 2/5 of calendars had been sold, the bookseller reduced the price of each calendar by $10. It is given that if all the calendars were sold, the bookseller made an overall profit of $3000. a)Find the total number of calendars he had originally. b)If only a further 100 calendars were sold after the price reduction and the rest were discarded, and the bookseller made an overall profit per cent of 20%, find the total cost of the calendars. Question 5 A shop spends $2400 on 1 batch of basketballs and footballs. There are 15 more baskerballs than footballs. The selling price of a basketball is 20% higher than that of a football. The selling price of each footballs is $60. a)If all the basketballs and footballs are sold, and the overall profit is $660, how many basketballs and footballs has the shop sold? Urgently waiting for help.....Thanks
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Question 1 Last year, Mrs Chan's weight was 3 time of her son's weight. This year, her son's weight increaes by 10% while her weight decreases by 10%. Mrs Chan is now 32kg heavier than her son. Find Mrs Chan's weight last year. let Mrs Chan's weight be 3x kg and her son be x kg 3x(1-10%) - x(1+10%) = 32 3x(0.9) - x(1.1) = 32 2.7x - 1.1x = 32 1.6x = 32 x= 20 therefore Mrs Chan's weight is 3 x 20 = 60kg her son is 20kg Question 2 A furniture manufacturer sold a chair and a table for $X and $2.5X respectively to a merchant. The merchant then sold the chair at a loss of 40% and the table at a profit of 40%. Did the merchant make an overall profit or loss, and by what per cent? the cost of chair and table: X + 2.5X = $3.5X profit of selling the chair: X(1-40%) = X(0.6) = $0.6X profit of selling the table: 2.5X(1+40%) = 2.5X(1.4) = $3.5X Total profit of selling both chair and table = 0.6X + 3.5X = $4.1X (4.1X - 3.5X) / 3.5X * 100% = 17.14% (round up to two decimials) therefore, the merchant make a overall profit of 17.14% Question 3 Dorothy bought a teddy bear and sold it at 20% profit to Kim. Kim bought a suit costing $100 and dressed the teddy bear up in the suit. Kim then sold the teddy bear in the suit to Karen for $442. Kim made a profit of 30%. What was the price that Dorothy paid for the teddy bear? Let the price that Dorothy paid for the teddy bear be $x then Dorothy sold to Kim at x(1+20%) = $1.2x to Kim Kim sold to Karen at (1.2x+100) x (1+30%) = 442 (1.2x+100) = 442 / 1.3 1.2x = 340 -100 1.2x = 240 x = 200 therefore the price that Dorothy paid for the teddy bear is $200 2009-11-29 16:41:07 補充： 4a)Find the total number of calendars he had originally. Let the number of calendars he had originally be x 18(2/5x) + (18-10)(1-2/5)x = 3000 36/5x + 24/5x = 3000 60/5x = 3000 12x = 3000 x = 250 therefore the number of calendars he had originally is 250. 2009-11-29 16:42:08 補充： 4(b) The new profit made: 18(2/5 * 250) + (18-10) * 100 = $2600 The the total cost of calendars are: 2600 / 20% = $13000 2009-11-29 16:42:14 補充： 5a) Let the number of footballs be x and the number of basketballs be (x +15) total selling price = [60x + (1+20%)(60)(x+15)] = 60x + 72x + 1080 = 132x +1080 overall profit is (132x + 1080) - 2400 = 660 132x = 1980 x=15 therefore, the shop is selling 15 football and (15+15) = 30 basdketballs no b?
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