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標題:
Latent heat
發問:
A cup of fruit juice is of mass 0.2 kg and temperature 70OC. If the specific heat capacity of the fruit juice is 4000 Jkg-1K-1, find the minimum amount of ice at 0OC that should be added to the juice in order to lower its temperature to 0OC. (Note: Specific latent heat of fusion of ice=3.34×105Jkg-1)
最佳解答:
Let m kg of ice should be added, then: Heat gain when ice melts at 0°C = m × 3.34 × 105 J Heat gain when juice drops to 0°C = 0.2 × 4200 × 70 J Threfore, m × 3.34 × 105 = 0.2 × 4200 × 70 m = 0.168 kg Therefore 0.168 kg of ice should be added. 2007-06-24 13:01:12 補充： Sorry for the typo mistake:4200 should be 4000But the 0.168 kg answer is correct.
其他解答:
Latent heat
發問:
A cup of fruit juice is of mass 0.2 kg and temperature 70OC. If the specific heat capacity of the fruit juice is 4000 Jkg-1K-1, find the minimum amount of ice at 0OC that should be added to the juice in order to lower its temperature to 0OC. (Note: Specific latent heat of fusion of ice=3.34×105Jkg-1)
最佳解答:
Let m kg of ice should be added, then: Heat gain when ice melts at 0°C = m × 3.34 × 105 J Heat gain when juice drops to 0°C = 0.2 × 4200 × 70 J Threfore, m × 3.34 × 105 = 0.2 × 4200 × 70 m = 0.168 kg Therefore 0.168 kg of ice should be added. 2007-06-24 13:01:12 補充： Sorry for the typo mistake:4200 should be 4000But the 0.168 kg answer is correct.
其他解答:
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